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比较严格的验证身份证号码的JS

时间:2009-10-11 08:47来源:未知 作者:大宝库 点击:读取中
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<html>
<head>
<title>身份证号是否有效验证</title>
</head>
<body>
请输入身份证号码:<input type="text" size="20" id="asidinput" /><input type="button" value="验证" onclick="alert(cidInfo(asidinput.value))" />
<script>
var aCity={11:"北京",12:"天津",13:"河北",14:"山西",15:"内蒙古",21:"辽宁",22:"吉林",23:"黑龙江",31:"上海",32:"江苏",33:"浙江",34:"安徽",35:"福建",36:"江西",37:"山东",41:"河南",42:"湖北",43:"湖南",44:"广东",45:"广西",46:"海南",50:"重庆",51:"四川",52:"贵州",53:"云南",54:"西藏",61:"陕西",62:"甘肃",63:"青海",64:"宁夏",65:"新疆",71:"台湾",81:"香港",82:"澳门",91:"国外"} 
function cidInfo(sId){
var iSum=0
var info=""
if(!/^d{17}(d|x)$/i.test(sId))return false;
sId=sId.replace(/x$/i,"a");
if(aCity[parseInt(sId.substr(0,2))]==null)return "Error:非法地区";
sBirthday=sId.substr(6,4)+"-"+Number(sId.substr(10,2))+"-"+Number(sId.substr(12,2));
var d=new Date(sBirthday.replace(/-/g,"/"))
if(sBirthday!=(d.getFullYear()+"-"+ (d.getMonth()+1) + "-" + d.getDate()))return "Error:非法生日";
for(var i = 17;i>=0;i --) iSum += (Math.pow(2,i) % 11) * parseInt(sId.charAt(17 - i),11)
if(iSum%11!=1)return "Error:非法证号";
return aCity[parseInt(sId.substr(0,2))]+","+sBirthday+","+(sId.substr(16,1)%2?"男":"女")
}
</script>
</body>
</html>

(责任编辑:大宝库)


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